(40x^2-4x+8)/8x

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Solution for (40x^2-4x+8)/8x equation: 


x in (-oo:+oo)

x*((40*x^2-(4*x)+8)/8) = 0

x*((40*x^2-4*x+8)/8) = 0

(x*(40*x^2-4*x+8))/8 = 0

40*x^2-4*x+8 = 0

4*(10*x^2-x+2) = 0

10*x^2-x+2 = 0

DELTA = (-1)^2-(2*4*10)

DELTA = -79

DELTA < 0

4 = 0

(4*x)/8 = 0

x = 0

x = 0

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